X^2-140+4x=180

Solution for X^2-140+4x=180 equation:

X^2-140+4X=180

We move all terms to the left:

X^2-140+4X-(180)=0

We add all the numbers together, and all the variables

X^2+4X-320=0

a = 1; b = 4; c = -320;
Δ = b2-4ac
Δ = 42-4·1·(-320)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-36}{2*1}=\frac{-40}{2}
=-20
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+36}{2*1}=\frac{32}{2}
=16
$